Base | Representation |
---|---|
bin | 10111111011111110… |
… | …10101111100011001 |
3 | 1020011121202100012121 |
4 | 23331333111330121 |
5 | 202304400101233 |
6 | 5523113141241 |
7 | 633315121033 |
oct | 137577257431 |
9 | 36147670177 |
10 | 12851175193 |
11 | 54a517614a |
12 | 25a79ba821 |
13 | 129a5c499c |
14 | 89caa8c53 |
15 | 50335592d |
hex | 2fdfd5f19 |
12851175193 has 2 divisors, whose sum is σ = 12851175194. Its totient is φ = 12851175192.
The previous prime is 12851175121. The next prime is 12851175199. The reversal of 12851175193 is 39157115821.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11661408144 + 1189767049 = 107988^2 + 34493^2 .
It is an emirp because it is prime and its reverse (39157115821) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12851175193 is a prime.
It is not a weakly prime, because it can be changed into another prime (12851175199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6425587596 + 6425587597.
It is an arithmetic number, because the mean of its divisors is an integer number (6425587597).
Almost surely, 212851175193 is an apocalyptic number.
It is an amenable number.
12851175193 is a deficient number, since it is larger than the sum of its proper divisors (1).
12851175193 is an equidigital number, since it uses as much as digits as its factorization.
12851175193 is an evil number, because the sum of its binary digits is even.
The product of its digits is 75600, while the sum is 43.
The spelling of 12851175193 in words is "twelve billion, eight hundred fifty-one million, one hundred seventy-five thousand, one hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •