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1286640704147 is a prime number
BaseRepresentation
bin10010101110010001110…
…000110001101010010011
311120000001012110220111212
4102232101300301222103
5132040020010013042
62423024035330335
7161646104352101
oct22562160615223
94500035426455
101286640704147
11456730153517
121894394509ab
1394439466356
14463b9212c71
15237061a0482
hex12b91c31a93

1286640704147 has 2 divisors, whose sum is σ = 1286640704148. Its totient is φ = 1286640704146.

The previous prime is 1286640704017. The next prime is 1286640704177. The reversal of 1286640704147 is 7414070466821.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1286640704147 - 28 = 1286640703891 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1286640704095 and 1286640704104.

It is not a weakly prime, because it can be changed into another prime (1286640704177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 643320352073 + 643320352074.

It is an arithmetic number, because the mean of its divisors is an integer number (643320352074).

Almost surely, 21286640704147 is an apocalyptic number.

1286640704147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1286640704147 is an equidigital number, since it uses as much as digits as its factorization.

1286640704147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1806336, while the sum is 50.

The spelling of 1286640704147 in words is "one trillion, two hundred eighty-six billion, six hundred forty million, seven hundred four thousand, one hundred forty-seven".