Base | Representation |
---|---|
bin | 10010101110010001110… |
… | …000110001101010010011 |
3 | 11120000001012110220111212 |
4 | 102232101300301222103 |
5 | 132040020010013042 |
6 | 2423024035330335 |
7 | 161646104352101 |
oct | 22562160615223 |
9 | 4500035426455 |
10 | 1286640704147 |
11 | 456730153517 |
12 | 1894394509ab |
13 | 94439466356 |
14 | 463b9212c71 |
15 | 237061a0482 |
hex | 12b91c31a93 |
1286640704147 has 2 divisors, whose sum is σ = 1286640704148. Its totient is φ = 1286640704146.
The previous prime is 1286640704017. The next prime is 1286640704177. The reversal of 1286640704147 is 7414070466821.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1286640704147 - 28 = 1286640703891 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1286640704095 and 1286640704104.
It is not a weakly prime, because it can be changed into another prime (1286640704177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 643320352073 + 643320352074.
It is an arithmetic number, because the mean of its divisors is an integer number (643320352074).
Almost surely, 21286640704147 is an apocalyptic number.
1286640704147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1286640704147 is an equidigital number, since it uses as much as digits as its factorization.
1286640704147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1806336, while the sum is 50.
The spelling of 1286640704147 in words is "one trillion, two hundred eighty-six billion, six hundred forty million, seven hundred four thousand, one hundred forty-seven".
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