Base | Representation |
---|---|
bin | 11101010000111011110111… |
… | …100000101011110110101011 |
3 | 121212201021122001121002012021 |
4 | 131100323313200223312223 |
5 | 113332214211442020043 |
6 | 1133423124531325311 |
7 | 36052532655435052 |
oct | 3520736740536653 |
9 | 555637561532167 |
10 | 128707142532523 |
11 | 38012435631485 |
12 | 12528381750837 |
13 | 56a8054179969 |
14 | 23ad65d473399 |
15 | ed2e7c7443ed |
hex | 750ef782bdab |
128707142532523 has 2 divisors, whose sum is σ = 128707142532524. Its totient is φ = 128707142532522.
The previous prime is 128707142532433. The next prime is 128707142532557. The reversal of 128707142532523 is 325235241707821.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-128707142532523 is a prime.
It is a super-2 number, since 2×1287071425325232 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (128707142532223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64353571266261 + 64353571266262.
It is an arithmetic number, because the mean of its divisors is an integer number (64353571266262).
Almost surely, 2128707142532523 is an apocalyptic number.
128707142532523 is a deficient number, since it is larger than the sum of its proper divisors (1).
128707142532523 is an equidigital number, since it uses as much as digits as its factorization.
128707142532523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5644800, while the sum is 52.
The spelling of 128707142532523 in words is "one hundred twenty-eight trillion, seven hundred seven billion, one hundred forty-two million, five hundred thirty-two thousand, five hundred twenty-three".
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