Base | Representation |
---|---|
bin | 111011111101011100… |
… | …0111011100001011011 |
3 | 110022100201211022222001 |
4 | 1313322320323201123 |
5 | 4102201344420301 |
6 | 135053015541431 |
7 | 12205605550042 |
oct | 1677270734133 |
9 | 408321738861 |
10 | 128763279451 |
11 | 4a676572734 |
12 | 20b5668a877 |
13 | c1b08c4421 |
14 | 633713b559 |
15 | 35394c2c01 |
hex | 1dfae3b85b |
128763279451 has 2 divisors, whose sum is σ = 128763279452. Its totient is φ = 128763279450.
The previous prime is 128763279371. The next prime is 128763279457. The reversal of 128763279451 is 154972367821.
It is a strong prime.
It is an emirp because it is prime and its reverse (154972367821) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 128763279451 - 211 = 128763277403 is a prime.
It is a super-2 number, since 2×1287632794512 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 128763279392 and 128763279401.
It is not a weakly prime, because it can be changed into another prime (128763279457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64381639725 + 64381639726.
It is an arithmetic number, because the mean of its divisors is an integer number (64381639726).
Almost surely, 2128763279451 is an apocalyptic number.
128763279451 is a deficient number, since it is larger than the sum of its proper divisors (1).
128763279451 is an equidigital number, since it uses as much as digits as its factorization.
128763279451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5080320, while the sum is 55.
The spelling of 128763279451 in words is "one hundred twenty-eight billion, seven hundred sixty-three million, two hundred seventy-nine thousand, four hundred fifty-one".
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