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1287801300140 = 22564390065007
BaseRepresentation
bin10010101111010110111…
…100000110010010101100
311120010001002100021220122
4102233112330012102230
5132044404113101030
62423335135104112
7162016626303635
oct22572674062254
94503032307818
101287801300140
11457176296463
12189702072038
1394592a42344
144648940688c
15237730058e5
hex12bd6f064ac

1287801300140 has 12 divisors (see below), whose sum is σ = 2704382730336. Its totient is φ = 515120520048.

The previous prime is 1287801300131. The next prime is 1287801300157. The reversal of 1287801300140 is 410031087821.

It is a self number, because there is not a number n which added to its sum of digits gives 1287801300140.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32195032484 + ... + 32195032523.

It is an arithmetic number, because the mean of its divisors is an integer number (225365227528).

Almost surely, 21287801300140 is an apocalyptic number.

1287801300140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1287801300140 is an abundant number, since it is smaller than the sum of its proper divisors (1416581430196).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1287801300140 is a wasteful number, since it uses less digits than its factorization.

1287801300140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64390065016 (or 64390065014 counting only the distinct ones).

The product of its (nonzero) digits is 10752, while the sum is 35.

Adding to 1287801300140 its reverse (410031087821), we get a palindrome (1697832387961).

The spelling of 1287801300140 in words is "one trillion, two hundred eighty-seven billion, eight hundred one million, three hundred thousand, one hundred forty".

Divisors: 1 2 4 5 10 20 64390065007 128780130014 257560260028 321950325035 643900650070 1287801300140