12887998231680 has 2688 divisors, whose sum is σ = 57954119675760. Its totient is φ = 2711751229440.

The previous prime is 12887998231673. The next prime is 12887998231709. The reversal of 12887998231680 is 8613289978821.

12887998231680 is a `hidden beast` number, since 1 + 2 + 88 + 79 + 98 + 2 + 316 + 80 = 666.

It can be written as a sum of positive squares in 8 ways, for example, as 8722382543424 + 4165615688256 = 2953368^2 + 2040984^2 .

It is a super-2 number, since 2×12887998231680² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (72).

It is a junction number, because it is equal to n+sod(n) for n = 12887998231599 and 12887998231608.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 335 ways as a sum of consecutive naturals, for example, 12476280444 + ... + 12476281476.

Almost surely, 2^{12887998231680} is an apocalyptic number.

12887998231680 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12887998231680, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (28977059837880).

12887998231680 is an abundant number, since it is smaller than the sum of its proper divisors (45066121444080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12887998231680 is a wasteful number, since it uses less digits than its factorization.

12887998231680 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1122 (or 1084 counting only the distinct ones).

The product of its (nonzero) digits is 167215104, while the sum is 72.

The spelling of 12887998231680 in words is "twelve trillion, eight hundred eighty-seven billion, nine hundred ninety-eight million, two hundred thirty-one thousand, six hundred eighty".