Search a number
-
+
12888520120067 is a prime number
BaseRepresentation
bin1011101110001101011110…
…1010011101011100000011
31200122010112010102212021112
42323203113222131130003
53142131142122320232
643224523203513535
72500110354302234
oct273432752353403
950563463385245
1012888520120067
114119a99671a19
121541a6b3888ab
137264c79c2217
14327b4449908b
151753d76bb4b2
hexbb8d7a9d703

12888520120067 has 2 divisors, whose sum is σ = 12888520120068. Its totient is φ = 12888520120066.

The previous prime is 12888520120043. The next prime is 12888520120079. The reversal of 12888520120067 is 76002102588821.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12888520120067 is a prime.

It is a super-2 number, since 2×128885201200672 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12888520119997 and 12888520120024.

It is not a weakly prime, because it can be changed into another prime (12888520126067) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6444260060033 + 6444260060034.

It is an arithmetic number, because the mean of its divisors is an integer number (6444260060034).

Almost surely, 212888520120067 is an apocalyptic number.

12888520120067 is a deficient number, since it is larger than the sum of its proper divisors (1).

12888520120067 is an equidigital number, since it uses as much as digits as its factorization.

12888520120067 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 860160, while the sum is 50.

The spelling of 12888520120067 in words is "twelve trillion, eight hundred eighty-eight billion, five hundred twenty million, one hundred twenty thousand, sixty-seven".