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12894672362311 = 47274354731113
BaseRepresentation
bin1011101110100100011001…
…0111011001101101000111
31200122201101212222011001101
42323221012113121231013
53142231242111043221
643231421455440531
72500416000426445
oct273510627315507
950581355864041
1012894672362311
114121666426643
1215430a7826147
13726c6849364c
143281695b7b95
15175647877d91
hexbba465d9b47

12894672362311 has 4 divisors (see below), whose sum is σ = 13169027093472. Its totient is φ = 12620317631152.

The previous prime is 12894672362309. The next prime is 12894672362323. The reversal of 12894672362311 is 11326327649821.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12894672362311 - 21 = 12894672362309 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12894672362381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 137177365510 + ... + 137177365603.

It is an arithmetic number, because the mean of its divisors is an integer number (3292256773368).

Almost surely, 212894672362311 is an apocalyptic number.

12894672362311 is a deficient number, since it is larger than the sum of its proper divisors (274354731161).

12894672362311 is an equidigital number, since it uses as much as digits as its factorization.

12894672362311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 274354731160.

The product of its digits is 5225472, while the sum is 55.

The spelling of 12894672362311 in words is "twelve trillion, eight hundred ninety-four billion, six hundred seventy-two million, three hundred sixty-two thousand, three hundred eleven".

Divisors: 1 47 274354731113 12894672362311