Base | Representation |
---|---|
bin | 1011101111011001011100… |
… | …1100011011000101111001 |
3 | 1200201002011100212210221212 |
4 | 2323312113030123011321 |
5 | 3142444423303401133 |
6 | 43242134541212505 |
7 | 2501431622644241 |
oct | 273662714330571 |
9 | 50632140783855 |
10 | 12908913340793 |
11 | 4127704056548 |
12 | 1545a00b61135 |
13 | 7283c79a6832 |
14 | 328b1aa9cb21 |
15 | 175bccc0c148 |
hex | bbd9731b179 |
12908913340793 has 2 divisors, whose sum is σ = 12908913340794. Its totient is φ = 12908913340792.
The previous prime is 12908913340789. The next prime is 12908913340849. The reversal of 12908913340793 is 39704331980921.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12006419040784 + 902494300009 = 3465028^2 + 949997^2 .
It is a cyclic number.
It is not a de Polignac number, because 12908913340793 - 22 = 12908913340789 is a prime.
It is not a weakly prime, because it can be changed into another prime (12908913340093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6454456670396 + 6454456670397.
It is an arithmetic number, because the mean of its divisors is an integer number (6454456670397).
Almost surely, 212908913340793 is an apocalyptic number.
It is an amenable number.
12908913340793 is a deficient number, since it is larger than the sum of its proper divisors (1).
12908913340793 is an equidigital number, since it uses as much as digits as its factorization.
12908913340793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8817984, while the sum is 59.
The spelling of 12908913340793 in words is "twelve trillion, nine hundred eight billion, nine hundred thirteen million, three hundred forty thousand, seven hundred ninety-three".
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