Base | Representation |
---|---|
bin | 11000000011000000… |
… | …00001100100000001 |
3 | 1020022201120201100002 |
4 | 30001200001210001 |
5 | 202414434332423 |
6 | 5533015405345 |
7 | 634631551016 |
oct | 140140014401 |
9 | 36281521302 |
10 | 12910074113 |
11 | 5525444842 |
12 | 2603683855 |
13 | 12a9877711 |
14 | 8a683b70d |
15 | 5085dc228 |
hex | 301801901 |
12910074113 has 2 divisors, whose sum is σ = 12910074114. Its totient is φ = 12910074112.
The previous prime is 12910074053. The next prime is 12910074143. The reversal of 12910074113 is 31147001921.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8428708864 + 4481365249 = 91808^2 + 66943^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12910074113 is a prime.
It is not a weakly prime, because it can be changed into another prime (12910074143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6455037056 + 6455037057.
It is an arithmetic number, because the mean of its divisors is an integer number (6455037057).
Almost surely, 212910074113 is an apocalyptic number.
It is an amenable number.
12910074113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12910074113 is an equidigital number, since it uses as much as digits as its factorization.
12910074113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 29.
The spelling of 12910074113 in words is "twelve billion, nine hundred ten million, seventy-four thousand, one hundred thirteen".
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