Base | Representation |
---|---|
bin | 1011101111100000000110… |
… | …1101001101000111101011 |
3 | 1200201020202220101201111201 |
4 | 2323320001231031013223 |
5 | 3143012103240203321 |
6 | 43243032134305031 |
7 | 2501524122005662 |
oct | 273700155150753 |
9 | 50636686351451 |
10 | 12910700319211 |
11 | 4128440826912 |
12 | 154621b4b8177 |
13 | 728620c87906 |
14 | 328c4a145dd9 |
15 | 175c84a42291 |
hex | bbe01b4d1eb |
12910700319211 has 2 divisors, whose sum is σ = 12910700319212. Its totient is φ = 12910700319210.
The previous prime is 12910700319119. The next prime is 12910700319221. The reversal of 12910700319211 is 11291300701921.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12910700319211 - 215 = 12910700286443 is a prime.
It is not a weakly prime, because it can be changed into another prime (12910700319221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6455350159605 + 6455350159606.
It is an arithmetic number, because the mean of its divisors is an integer number (6455350159606).
Almost surely, 212910700319211 is an apocalyptic number.
12910700319211 is a deficient number, since it is larger than the sum of its proper divisors (1).
12910700319211 is an equidigital number, since it uses as much as digits as its factorization.
12910700319211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 37.
The spelling of 12910700319211 in words is "twelve trillion, nine hundred ten billion, seven hundred million, three hundred nineteen thousand, two hundred eleven".
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