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129125696243 is a prime number
BaseRepresentation
bin111100001000001111…
…1011100001011110011
3110100021222210000100012
41320100133130023303
54103422134234433
6135153003445135
712220566210545
oct1702037341363
9410258700305
10129125696243
114a8420a8845
1221037b267ab
13c23aa0722b
14636d31b695
15355b210848
hex1e107dc2f3

129125696243 has 2 divisors, whose sum is σ = 129125696244. Its totient is φ = 129125696242.

The previous prime is 129125696173. The next prime is 129125696251. The reversal of 129125696243 is 342696521921.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 129125696243 - 210 = 129125695219 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 129125696191 and 129125696200.

It is not a weakly prime, because it can be changed into another prime (129125696443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64562848121 + 64562848122.

It is an arithmetic number, because the mean of its divisors is an integer number (64562848122).

Almost surely, 2129125696243 is an apocalyptic number.

129125696243 is a deficient number, since it is larger than the sum of its proper divisors (1).

129125696243 is an equidigital number, since it uses as much as digits as its factorization.

129125696243 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1399680, while the sum is 50.

The spelling of 129125696243 in words is "one hundred twenty-nine billion, one hundred twenty-five million, six hundred ninety-six thousand, two hundred forty-three".