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129139113128659 is a prime number
BaseRepresentation
bin11101010111001110001010…
…111101101111001011010011
3121221020120121211111000021021
4131113032022331233023103
5113411303400430104114
61134353404540340311
736125664416063134
oct3527161275571323
9557216554430237
10129139113128659
1138169654790957
1212598037844697
1357099c62008ba
1423c651b683c8b
15ede310c6c024
hex75738af6f2d3

129139113128659 has 2 divisors, whose sum is σ = 129139113128660. Its totient is φ = 129139113128658.

The previous prime is 129139113128569. The next prime is 129139113128693. The reversal of 129139113128659 is 956821311931921.

Together with previous prime (129139113128569) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 129139113128659 - 233 = 129130523194067 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 129139113128597 and 129139113128606.

It is not a weakly prime, because it can be changed into another prime (129139113128959) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64569556564329 + 64569556564330.

It is an arithmetic number, because the mean of its divisors is an integer number (64569556564330).

Almost surely, 2129139113128659 is an apocalyptic number.

129139113128659 is a deficient number, since it is larger than the sum of its proper divisors (1).

129139113128659 is an equidigital number, since it uses as much as digits as its factorization.

129139113128659 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6298560, while the sum is 61.

The spelling of 129139113128659 in words is "one hundred twenty-nine trillion, one hundred thirty-nine billion, one hundred thirteen million, one hundred twenty-eight thousand, six hundred fifty-nine".