Base | Representation |
---|---|
bin | 1011110000000101100010… |
… | …1111101001110001110011 |
3 | 1200202012201022121110221012 |
4 | 2330001120233221301303 |
5 | 3143143144112411032 |
6 | 43251413313021135 |
7 | 2502331146154202 |
oct | 274013057516163 |
9 | 50665638543835 |
10 | 12920750513267 |
11 | 4131728904413 |
12 | 15481652547ab |
13 | 72956319a8bc |
14 | 329520c13239 |
15 | 1761720176b2 |
hex | bc058be9c73 |
12920750513267 has 2 divisors, whose sum is σ = 12920750513268. Its totient is φ = 12920750513266.
The previous prime is 12920750513239. The next prime is 12920750513287. The reversal of 12920750513267 is 76231505702921.
It is a strong prime.
It is an emirp because it is prime and its reverse (76231505702921) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12920750513267 - 212 = 12920750509171 is a prime.
It is not a weakly prime, because it can be changed into another prime (12920750513227) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6460375256633 + 6460375256634.
It is an arithmetic number, because the mean of its divisors is an integer number (6460375256634).
Almost surely, 212920750513267 is an apocalyptic number.
12920750513267 is a deficient number, since it is larger than the sum of its proper divisors (1).
12920750513267 is an equidigital number, since it uses as much as digits as its factorization.
12920750513267 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1587600, while the sum is 50.
The spelling of 12920750513267 in words is "twelve trillion, nine hundred twenty billion, seven hundred fifty million, five hundred thirteen thousand, two hundred sixty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •