Base | Representation |
---|---|
bin | 11000000101111000… |
… | …11101010010110011 |
3 | 1020101102011202210101 |
4 | 30002330131102303 |
5 | 202442140224242 |
6 | 5535243013231 |
7 | 635344530604 |
oct | 140274352263 |
9 | 36342152711 |
10 | 12934304947 |
11 | 5538094823 |
12 | 260b80a217 |
13 | 12b18ac7a5 |
14 | 8a9b47dab |
15 | 50a7c69b7 |
hex | 302f1d4b3 |
12934304947 has 2 divisors, whose sum is σ = 12934304948. Its totient is φ = 12934304946.
The previous prime is 12934304923. The next prime is 12934304951. The reversal of 12934304947 is 74940343921.
12934304947 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (74940343921) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12934304947 - 215 = 12934272179 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12934304897 and 12934304906.
It is not a weakly prime, because it can be changed into another prime (12934304447) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6467152473 + 6467152474.
It is an arithmetic number, because the mean of its divisors is an integer number (6467152474).
Almost surely, 212934304947 is an apocalyptic number.
12934304947 is a deficient number, since it is larger than the sum of its proper divisors (1).
12934304947 is an equidigital number, since it uses as much as digits as its factorization.
12934304947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 653184, while the sum is 46.
The spelling of 12934304947 in words is "twelve billion, nine hundred thirty-four million, three hundred four thousand, nine hundred forty-seven".
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