Base | Representation |
---|---|
bin | 1011110001000001011111… |
… | …0110001011100011101000 |
3 | 1200210202020201210002102221 |
4 | 2330100113312023203220 |
5 | 3143424122420342012 |
6 | 43303034124203424 |
7 | 2503440665010433 |
oct | 274202766134350 |
9 | 50722221702387 |
10 | 12936841574632 |
11 | 4138535895a38 |
12 | 154b2b6099574 |
13 | 72ac28a87ba1 |
14 | 32a209cca81a |
15 | 1767b49e9507 |
hex | bc417d8b8e8 |
12936841574632 has 8 divisors (see below), whose sum is σ = 24256577952450. Its totient is φ = 6468420787312.
The previous prime is 12936841574617. The next prime is 12936841574633. The reversal of 12936841574632 is 23647514863921.
12936841574632 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in only one way, i.e., 12239740149156 + 697101425476 = 3498534^2 + 834926^2 .
It is a tau number, because it is divible by the number of its divisors (8).
It is not an unprimeable number, because it can be changed into a prime (12936841574633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 808552598407 + ... + 808552598422.
Almost surely, 212936841574632 is an apocalyptic number.
It is an amenable number.
12936841574632 is a deficient number, since it is larger than the sum of its proper divisors (11319736377818).
12936841574632 is a wasteful number, since it uses less digits than its factorization.
12936841574632 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1617105196835 (or 1617105196831 counting only the distinct ones).
The product of its digits is 52254720, while the sum is 61.
The spelling of 12936841574632 in words is "twelve trillion, nine hundred thirty-six billion, eight hundred forty-one million, five hundred seventy-four thousand, six hundred thirty-two".
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