Base | Representation |
---|---|
bin | 10010110100111110000… |
… | …111110010011010000011 |
3 | 11120200121001111010020102 |
4 | 102310332013302122003 |
5 | 132144224302304323 |
6 | 2430213123033015 |
7 | 162322151213231 |
oct | 22647607623203 |
9 | 4520531433212 |
10 | 1293827384963 |
11 | 459788913153 |
12 | 18a90420b76b |
13 | 95013341cc9 |
14 | 4689b885951 |
15 | 239c7092328 |
hex | 12d3e1f2683 |
1293827384963 has 2 divisors, whose sum is σ = 1293827384964. Its totient is φ = 1293827384962.
The previous prime is 1293827384959. The next prime is 1293827384989. The reversal of 1293827384963 is 3694837283921.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1293827384963 - 22 = 1293827384959 is a prime.
It is a super-2 number, since 2×12938273849632 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1293827384963.
It is not a weakly prime, because it can be changed into another prime (1293827384263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 646913692481 + 646913692482.
It is an arithmetic number, because the mean of its divisors is an integer number (646913692482).
Almost surely, 21293827384963 is an apocalyptic number.
1293827384963 is a deficient number, since it is larger than the sum of its proper divisors (1).
1293827384963 is an equidigital number, since it uses as much as digits as its factorization.
1293827384963 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 94058496, while the sum is 65.
The spelling of 1293827384963 in words is "one trillion, two hundred ninety-three billion, eight hundred twenty-seven million, three hundred eighty-four thousand, nine hundred sixty-three".
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