Base | Representation |
---|---|
bin | 1011110001001110110001… |
… | …1110110111010001101001 |
3 | 1200211002110100112112202021 |
4 | 2330103230132313101221 |
5 | 3144003424201244012 |
6 | 43304424122504441 |
7 | 2503625253500452 |
oct | 274235436672151 |
9 | 50732410475667 |
10 | 12940409009257 |
11 | 4139aa6591414 |
12 | 154bb30965121 |
13 | 72b376ba5452 |
14 | 32a467a00129 |
15 | 176922cc7007 |
hex | bc4ec7b7469 |
12940409009257 has 2 divisors, whose sum is σ = 12940409009258. Its totient is φ = 12940409009256.
The previous prime is 12940409009233. The next prime is 12940409009347. The reversal of 12940409009257 is 75290090404921.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12105312774361 + 835096234896 = 3479269^2 + 913836^2 .
It is a cyclic number.
It is not a de Polignac number, because 12940409009257 - 239 = 12390653195369 is a prime.
It is not a weakly prime, because it can be changed into another prime (12940409000257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6470204504628 + 6470204504629.
It is an arithmetic number, because the mean of its divisors is an integer number (6470204504629).
Almost surely, 212940409009257 is an apocalyptic number.
It is an amenable number.
12940409009257 is a deficient number, since it is larger than the sum of its proper divisors (1).
12940409009257 is an equidigital number, since it uses as much as digits as its factorization.
12940409009257 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1632960, while the sum is 52.
The spelling of 12940409009257 in words is "twelve trillion, nine hundred forty billion, four hundred nine million, nine thousand, two hundred fifty-seven".
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