Base | Representation |
---|---|
bin | 1011110001101010001110… |
… | …1111011011101110001011 |
3 | 1200211210110221122001001102 |
4 | 2330122203233123232023 |
5 | 3144114022302110132 |
6 | 43312043301412015 |
7 | 2504306010533102 |
oct | 274324357335613 |
9 | 50753427561042 |
10 | 12947778550667 |
11 | 4142138497a04 |
12 | 1551448a0a00b |
13 | 72bc7c91703c |
14 | 32a966673039 |
15 | 176c04c89c62 |
hex | bc6a3bdbb8b |
12947778550667 has 2 divisors, whose sum is σ = 12947778550668. Its totient is φ = 12947778550666.
The previous prime is 12947778550627. The next prime is 12947778550691. The reversal of 12947778550667 is 76605587774921.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12947778550667 is a prime.
It is a super-2 number, since 2×129477785506672 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12947778550594 and 12947778550603.
It is not a weakly prime, because it can be changed into another prime (12947778550627) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6473889275333 + 6473889275334.
It is an arithmetic number, because the mean of its divisors is an integer number (6473889275334).
Almost surely, 212947778550667 is an apocalyptic number.
12947778550667 is a deficient number, since it is larger than the sum of its proper divisors (1).
12947778550667 is an equidigital number, since it uses as much as digits as its factorization.
12947778550667 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1244678400, while the sum is 74.
The spelling of 12947778550667 in words is "twelve trillion, nine hundred forty-seven billion, seven hundred seventy-eight million, five hundred fifty thousand, six hundred sixty-seven".
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