1294933162147 has 2 divisors, whose sum is σ = 1294933162148. Its totient is φ = 1294933162146.

The previous prime is 1294933162141. The next prime is 1294933162157. The reversal of 1294933162147 is 7412613394921.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1294933162147 is a prime.

It is a super-3 number, since 3×1294933162147³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1294933162094 and 1294933162103.

It is not a weakly prime, because it can be changed into another prime (1294933162141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 647466581073 + 647466581074.

It is an arithmetic number, because the mean of its divisors is an integer number (647466581074).

Almost surely, 2^{1294933162147} is an apocalyptic number.

1294933162147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1294933162147 is an equidigital number, since it uses as much as digits as its factorization.

1294933162147 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1959552, while the sum is 52.

The spelling of 1294933162147 in words is "one trillion, two hundred ninety-four billion, nine hundred thirty-three million, one hundred sixty-two thousand, one hundred forty-seven".