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129812701035 = 35312503111533
BaseRepresentation
bin111100011100101110…
…0001001111101101011
3110102001212111110202010
41320321130021331223
54111324022413120
6135345104411003
712243610516143
oct1707134117553
9412055443663
10129812701035
11500649816a6
12211aa016a63
13c31a146644
1463d6671923
15359b6b77e0
hex1e39709f6b

129812701035 has 32 divisors (see below), whose sum is σ = 214487912448. Its totient is φ = 66972735360.

The previous prime is 129812701009. The next prime is 129812701043. The reversal of 129812701035 is 530107218921.

It is a happy number.

It is not a de Polignac number, because 129812701035 - 27 = 129812700907 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 129812700984 and 129812701002.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1108129 + ... + 1219661.

It is an arithmetic number, because the mean of its divisors is an integer number (6702747264).

Almost surely, 2129812701035 is an apocalyptic number.

129812701035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

129812701035 is a deficient number, since it is larger than the sum of its proper divisors (84675211413).

129812701035 is a wasteful number, since it uses less digits than its factorization.

129812701035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 114075.

The product of its (nonzero) digits is 30240, while the sum is 39.

Adding to 129812701035 its reverse (530107218921), we get a palindrome (659919919956).

The spelling of 129812701035 in words is "one hundred twenty-nine billion, eight hundred twelve million, seven hundred one thousand, thirty-five".

Divisors: 1 3 5 15 31 93 155 465 2503 7509 12515 37545 77593 111533 232779 334599 387965 557665 1163895 1672995 3457523 10372569 17287615 51862845 279167099 837501297 1395835495 4187506485 8654180069 25962540207 43270900345 129812701035