Base | Representation |
---|---|
bin | 111100011100101110… |
… | …0001001111101101011 |
3 | 110102001212111110202010 |
4 | 1320321130021331223 |
5 | 4111324022413120 |
6 | 135345104411003 |
7 | 12243610516143 |
oct | 1707134117553 |
9 | 412055443663 |
10 | 129812701035 |
11 | 500649816a6 |
12 | 211aa016a63 |
13 | c31a146644 |
14 | 63d6671923 |
15 | 359b6b77e0 |
hex | 1e39709f6b |
129812701035 has 32 divisors (see below), whose sum is σ = 214487912448. Its totient is φ = 66972735360.
The previous prime is 129812701009. The next prime is 129812701043. The reversal of 129812701035 is 530107218921.
It is a happy number.
It is not a de Polignac number, because 129812701035 - 27 = 129812700907 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 129812700984 and 129812701002.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1108129 + ... + 1219661.
It is an arithmetic number, because the mean of its divisors is an integer number (6702747264).
Almost surely, 2129812701035 is an apocalyptic number.
129812701035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
129812701035 is a deficient number, since it is larger than the sum of its proper divisors (84675211413).
129812701035 is a wasteful number, since it uses less digits than its factorization.
129812701035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 114075.
The product of its (nonzero) digits is 30240, while the sum is 39.
Adding to 129812701035 its reverse (530107218921), we get a palindrome (659919919956).
The spelling of 129812701035 in words is "one hundred twenty-nine billion, eight hundred twelve million, seven hundred one thousand, thirty-five".
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