Base | Representation |
---|---|
bin | 1011110011100111010111… |
… | …0011011100101000011000 |
3 | 1200222000011211100000000000 |
4 | 2330321311303130220120 |
5 | 3200141320100330100 |
6 | 43335320303213000 |
7 | 2506605250621530 |
oct | 274716563345030 |
9 | 50860154300000 |
10 | 12981367589400 |
11 | 4155404642951 |
12 | 1557a618a7160 |
13 | 7321a3721ca2 |
14 | 32c4316164c0 |
15 | 177a1da0c900 |
hex | bce75cdca18 |
12981367589400 has 1152 divisors, whose sum is σ = 54801242496000. Its totient is φ = 2791723345920.
The previous prime is 12981367589381. The next prime is 12981367589473. The reversal of 12981367589400 is 498576318921.
12981367589400 is a `hidden beast` number, since 1 + 2 + 9 + 8 + 1 + 3 + 6 + 7 + 589 + 40 + 0 = 666.
It is a super-2 number, since 2×129813675894002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (63).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 4216097061 + ... + 4216100139.
It is an arithmetic number, because the mean of its divisors is an integer number (47570523000).
It is a 1-persistent number, because it is pandigital, but 2⋅12981367589400 = 25962735178800 is not.
Almost surely, 212981367589400 is an apocalyptic number.
12981367589400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12981367589400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (27400621248000).
12981367589400 is an abundant number, since it is smaller than the sum of its proper divisors (41819874906600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12981367589400 is an equidigital number, since it uses as much as digits as its factorization.
12981367589400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3152 (or 3113 counting only the distinct ones).
The product of its (nonzero) digits is 26127360, while the sum is 63.
The spelling of 12981367589400 in words is "twelve trillion, nine hundred eighty-one billion, three hundred sixty-seven million, five hundred eighty-nine thousand, four hundred".
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