Base | Representation |
---|---|
bin | 1011110100010100011101… |
… | …0010111101010110111011 |
3 | 1201000011102102100002012001 |
4 | 2331011013102331112323 |
5 | 3200341112342111101 |
6 | 43345041351401431 |
7 | 2510514232405504 |
oct | 275050722752673 |
9 | 51004372302161 |
10 | 12993472222651 |
11 | 415a55636aa88 |
12 | 155a27b683277 |
13 | 73338246017b |
14 | 32cc5d0adbab |
15 | 177ecb54a901 |
hex | bd1474bd5bb |
12993472222651 has 8 divisors (see below), whose sum is σ = 13128520035680. Its totient is φ = 12858446746368.
The previous prime is 12993472222649. The next prime is 12993472222697. The reversal of 12993472222651 is 15622227439921.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12993472222651 - 21 = 12993472222649 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12993472222592 and 12993472222601.
It is not an unprimeable number, because it can be changed into a prime (12993472222751) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4413456 + ... + 6742813.
It is an arithmetic number, because the mean of its divisors is an integer number (1641065004460).
Almost surely, 212993472222651 is an apocalyptic number.
12993472222651 is a deficient number, since it is larger than the sum of its proper divisors (135047813029).
12993472222651 is a wasteful number, since it uses less digits than its factorization.
12993472222651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11168373.
The product of its digits is 6531840, while the sum is 55.
The spelling of 12993472222651 in words is "twelve trillion, nine hundred ninety-three billion, four hundred seventy-two million, two hundred twenty-two thousand, six hundred fifty-one".
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