Base | Representation |
---|---|
bin | 1011110100100101110101… |
… | …0110101001100100110011 |
3 | 1201000121110112102100012222 |
4 | 2331021131112221210303 |
5 | 3200430141114144433 |
6 | 43351132315311255 |
7 | 2511040646501516 |
oct | 275113526514463 |
9 | 51017415370188 |
10 | 12998137256243 |
11 | 416152a690847 |
12 | 155b161a4b52b |
13 | 733946a9a589 |
14 | 32d182898d7d |
15 | 1781a0d87b98 |
hex | bd25d5a9933 |
12998137256243 has 2 divisors, whose sum is σ = 12998137256244. Its totient is φ = 12998137256242.
The previous prime is 12998137256171. The next prime is 12998137256353. The reversal of 12998137256243 is 34265273189921.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12998137256243 - 210 = 12998137255219 is a prime.
It is not a weakly prime, because it can be changed into another prime (12998137250243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6499068628121 + 6499068628122.
It is an arithmetic number, because the mean of its divisors is an integer number (6499068628122).
Almost surely, 212998137256243 is an apocalyptic number.
12998137256243 is a deficient number, since it is larger than the sum of its proper divisors (1).
12998137256243 is an equidigital number, since it uses as much as digits as its factorization.
12998137256243 is an evil number, because the sum of its binary digits is even.
The product of its digits is 39191040, while the sum is 62.
The spelling of 12998137256243 in words is "twelve trillion, nine hundred ninety-eight billion, one hundred thirty-seven million, two hundred fifty-six thousand, two hundred forty-three".
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