Base | Representation |
---|---|
bin | 11101100011101111111100… |
… | …100111010110101011111011 |
3 | 122001021212202110002011111101 |
4 | 131203233330213112223323 |
5 | 114014410011402314003 |
6 | 1140253103123312231 |
7 | 36245122343021155 |
oct | 3543577447265373 |
9 | 561255673064441 |
10 | 130000013323003 |
11 | 38470772477a7a |
12 | 126b6a5951b677 |
13 | 576cc4426b415 |
14 | 2416069c69ad5 |
15 | 10068ea82b11d |
hex | 763bfc9d6afb |
130000013323003 has 2 divisors, whose sum is σ = 130000013323004. Its totient is φ = 130000013323002.
The previous prime is 130000013322943. The next prime is 130000013323031. The reversal of 130000013323003 is 300323310000031.
It is a strong prime.
It is an emirp because it is prime and its reverse (300323310000031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130000013323003 - 213 = 130000013314811 is a prime.
It is not a weakly prime, because it can be changed into another prime (130000013323043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000006661501 + 65000006661502.
It is an arithmetic number, because the mean of its divisors is an integer number (65000006661502).
Almost surely, 2130000013323003 is an apocalyptic number.
130000013323003 is a deficient number, since it is larger than the sum of its proper divisors (1).
130000013323003 is an equidigital number, since it uses as much as digits as its factorization.
130000013323003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 19.
Adding to 130000013323003 its reverse (300323310000031), we get a palindrome (430323323323034).
The spelling of 130000013323003 in words is "one hundred thirty trillion, thirteen million, three hundred twenty-three thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •