Base | Representation |
---|---|
bin | 10010111010101110000… |
… | …111011001100110011100 |
3 | 11121021112022210102220111 |
4 | 102322232013121212130 |
5 | 132244400313030334 |
6 | 2433113511255404 |
7 | 162631146501163 |
oct | 22725607314634 |
9 | 4537468712814 |
10 | 1300001298844 |
11 | 46136692a016 |
12 | 18bb4797a564 |
13 | 957884606a1 |
14 | 46cc58063da |
15 | 23c390d0064 |
hex | 12eae1d999c |
1300001298844 has 12 divisors (see below), whose sum is σ = 2277669339064. Its totient is φ = 649238630544.
The previous prime is 1300001298767. The next prime is 1300001298877. The reversal of 1300001298844 is 4488921000031.
It is a junction number, because it is equal to n+sod(n) for n = 1300001298797 and 1300001298806.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190500882 + ... + 190507705.
Almost surely, 21300001298844 is an apocalyptic number.
It is an amenable number.
1300001298844 is a deficient number, since it is larger than the sum of its proper divisors (977668040220).
1300001298844 is a wasteful number, since it uses less digits than its factorization.
1300001298844 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 381009444 (or 381009442 counting only the distinct ones).
The product of its (nonzero) digits is 55296, while the sum is 40.
Adding to 1300001298844 its reverse (4488921000031), we get a palindrome (5788922298875).
The spelling of 1300001298844 in words is "one trillion, three hundred billion, one million, two hundred ninety-eight thousand, eight hundred forty-four".
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