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1300001953 is a prime number
BaseRepresentation
bin100110101111100…
…0111010010100001
310100121011221102111
41031133013102201
510130300030303
6332555315321
744133556105
oct11537072241
93317157374
101300001953
116078a9788
1230344bb41
13179438b33
14c4921905
15791e0b6d
hex4d7c74a1

1300001953 has 2 divisors, whose sum is σ = 1300001954. Its totient is φ = 1300001952.

The previous prime is 1300001933. The next prime is 1300001971. The reversal of 1300001953 is 3591000031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1260463009 + 39538944 = 35503^2 + 6288^2 .

It is an emirp because it is prime and its reverse (3591000031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1300001953 is a prime.

It is not a weakly prime, because it can be changed into another prime (1300001903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650000976 + 650000977.

It is an arithmetic number, because the mean of its divisors is an integer number (650000977).

Almost surely, 21300001953 is an apocalyptic number.

It is an amenable number.

1300001953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300001953 is an equidigital number, since it uses as much as digits as its factorization.

1300001953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 405, while the sum is 22.

The square root of 1300001953 is about 36055.5398378668. The cubic root of 1300001953 is about 1091.3934295968.

Adding to 1300001953 its reverse (3591000031), we get a palindrome (4891001984).

The spelling of 1300001953 in words is "one billion, three hundred million, one thousand, nine hundred fifty-three".