Base | Representation |
---|---|
bin | 11101100011110000001001… |
… | …101010101100000111000001 |
3 | 122001021220022201010101211022 |
4 | 131203300021222230013001 |
5 | 114014410433432112433 |
6 | 1140253140544555225 |
7 | 36245130642220025 |
oct | 3543601152540701 |
9 | 561256281111738 |
10 | 130000232300993 |
11 | 3847087504241a |
12 | 126b6aba922b15 |
13 | 576cc7a73b8b2 |
14 | 241608ad8c385 |
15 | 100690eb83698 |
hex | 763c09aac1c1 |
130000232300993 has 2 divisors, whose sum is σ = 130000232300994. Its totient is φ = 130000232300992.
The previous prime is 130000232300977. The next prime is 130000232301011. The reversal of 130000232300993 is 399003232000031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 70313977227649 + 59686255073344 = 8385343^2 + 7725688^2 .
It is a cyclic number.
It is not a de Polignac number, because 130000232300993 - 24 = 130000232300977 is a prime.
It is a super-3 number, since 3×1300002323009933 (a number of 43 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (130000232300923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000116150496 + 65000116150497.
It is an arithmetic number, because the mean of its divisors is an integer number (65000116150497).
Almost surely, 2130000232300993 is an apocalyptic number.
It is an amenable number.
130000232300993 is a deficient number, since it is larger than the sum of its proper divisors (1).
130000232300993 is an equidigital number, since it uses as much as digits as its factorization.
130000232300993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26244, while the sum is 35.
The spelling of 130000232300993 in words is "one hundred thirty trillion, two hundred thirty-two million, three hundred thousand, nine hundred ninety-three".
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