Base | Representation |
---|---|
bin | 11101100011110000001111… |
… | …000101001011001010100111 |
3 | 122001021220120001000222211110 |
4 | 131203300033011023022213 |
5 | 114014411130210130043 |
6 | 1140253153551440103 |
7 | 36245133124234503 |
oct | 3543601705131247 |
9 | 561256501028743 |
10 | 130000323130023 |
11 | 3847091133a635 |
12 | 126b6b25226033 |
13 | 576cc934c0c98 |
14 | 2416099073303 |
15 | 1006917b25b33 |
hex | 763c0f14b2a7 |
130000323130023 has 8 divisors (see below), whose sum is σ = 173540359843200. Its totient is φ = 86563584251768.
The previous prime is 130000323130021. The next prime is 130000323130049. The reversal of 130000323130023 is 320031323000031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130000323130023 - 21 = 130000323130021 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130000323130021) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25824455793 + ... + 25824460826.
It is an arithmetic number, because the mean of its divisors is an integer number (21692544980400).
Almost surely, 2130000323130023 is an apocalyptic number.
130000323130023 is a deficient number, since it is larger than the sum of its proper divisors (43540036713177).
130000323130023 is an equidigital number, since it uses as much as digits as its factorization.
130000323130023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51648917461.
The product of its (nonzero) digits is 972, while the sum is 21.
Adding to 130000323130023 its reverse (320031323000031), we get a palindrome (450031646130054).
The spelling of 130000323130023 in words is "one hundred thirty trillion, three hundred twenty-three million, one hundred thirty thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •