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130000401111000 = 23353759104923649
BaseRepresentation
bin11101100011110000010011…
…101110101001011111011000
3122001021220202110202211121210
4131203300103232221133120
5114014411310141023000
61140253205415103120
736245135062121340
oct3543602356513730
9561256673684553
10130000401111000
1138470951361922
12126b6b47371aa0
13576cca66c5384
1424160a5571d20
15100691e8cb350
hex763c13ba97d8

130000401111000 has 256 divisors, whose sum is σ = 471400974720000. Its totient is φ = 29210743603200.

The previous prime is 130000401110969. The next prime is 130000401111011. The reversal of 130000401111000 is 111104000031.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 51222825 + ... + 53700824.

It is an arithmetic number, because the mean of its divisors is an integer number (1841410057500).

Almost surely, 2130000401111000 is an apocalyptic number.

130000401111000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130000401111000 is an abundant number, since it is smaller than the sum of its proper divisors (341400573609000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130000401111000 is a wasteful number, since it uses less digits than its factorization.

130000401111000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 104923739 (or 104923725 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 130000401111000 its reverse (111104000031), we get a palindrome (130111505111031).

The spelling of 130000401111000 in words is "one hundred thirty trillion, four hundred one million, one hundred eleven thousand".