Base | Representation |
---|---|
bin | 10010111010101110010… |
… | …010001011011100010001 |
3 | 11121021112112002222212221 |
4 | 102322232102023130101 |
5 | 132244402023440213 |
6 | 2433114052021041 |
7 | 162631212510100 |
oct | 22725622133421 |
9 | 4537475088787 |
10 | 1300004124433 |
11 | 461368489a13 |
12 | 18bb48901781 |
13 | 95788c0c831 |
14 | 46cc5d40037 |
15 | 23c3948c38d |
hex | 12eae48b711 |
1300004124433 has 48 divisors (see below), whose sum is σ = 1687983079680. Its totient is φ = 992070084096.
The previous prime is 1300004124431. The next prime is 1300004124437. The reversal of 1300004124433 is 3344214000031.
It is not a de Polignac number, because 1300004124433 - 21 = 1300004124431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1300004124398 and 1300004124407.
It is not an unprimeable number, because it can be changed into a prime (1300004124431) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 10654216 + ... + 10775542.
It is an arithmetic number, because the mean of its divisors is an integer number (35166314160).
Almost surely, 21300004124433 is an apocalyptic number.
It is an amenable number.
1300004124433 is a deficient number, since it is larger than the sum of its proper divisors (387978955247).
1300004124433 is a wasteful number, since it uses less digits than its factorization.
1300004124433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 122054 (or 122047 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 1300004124433 its reverse (3344214000031), we get a palindrome (4644218124464).
The spelling of 1300004124433 in words is "one trillion, three hundred billion, four million, one hundred twenty-four thousand, four hundred thirty-three".
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