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13000101041 is a prime number
BaseRepresentation
bin11000001101101110…
…11100110010110001
31020112222222120001202
430012313130302301
5203111011213131
65545553140545
7640104015134
oct140667346261
936488876052
1013000101041
115571244364
12262985a755
1312c24089a5
148b479421b
15511471bcb
hex306ddccb1

13000101041 has 2 divisors, whose sum is σ = 13000101042. Its totient is φ = 13000101040.

The previous prime is 13000101031. The next prime is 13000101047. The reversal of 13000101041 is 14010100031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10371385600 + 2628715441 = 101840^2 + 51271^2 .

It is a cyclic number.

It is not a de Polignac number, because 13000101041 - 230 = 11926359217 is a prime.

It is not a weakly prime, because it can be changed into another prime (13000101047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500050520 + 6500050521.

It is an arithmetic number, because the mean of its divisors is an integer number (6500050521).

Almost surely, 213000101041 is an apocalyptic number.

It is an amenable number.

13000101041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000101041 is an equidigital number, since it uses as much as digits as its factorization.

13000101041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 13000101041 its reverse (14010100031), we get a palindrome (27010201072).

The spelling of 13000101041 in words is "thirteen billion, one hundred one thousand, forty-one".