Base | Representation |
---|---|
bin | 11101100011110000111000… |
… | …000110011010100100100011 |
3 | 122001021222022222222201112201 |
4 | 131203300320012122210203 |
5 | 114014414032344233443 |
6 | 1140253350134034031 |
7 | 36245156151613525 |
oct | 3543607006324443 |
9 | 561258288881481 |
10 | 130001011321123 |
11 | 38471134853808 |
12 | 126b70977a8917 |
13 | 5770072c57357 |
14 | 2416122615a15 |
15 | 100695826434d |
hex | 763c3819a923 |
130001011321123 has 2 divisors, whose sum is σ = 130001011321124. Its totient is φ = 130001011321122.
The previous prime is 130001011321091. The next prime is 130001011321133. The reversal of 130001011321123 is 321123110100031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130001011321123 - 25 = 130001011321091 is a prime.
It is a super-2 number, since 2×1300010113211232 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 130001011321123.
It is not a weakly prime, because it can be changed into another prime (130001011321133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000505660561 + 65000505660562.
It is an arithmetic number, because the mean of its divisors is an integer number (65000505660562).
Almost surely, 2130001011321123 is an apocalyptic number.
130001011321123 is a deficient number, since it is larger than the sum of its proper divisors (1).
130001011321123 is an equidigital number, since it uses as much as digits as its factorization.
130001011321123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 130001011321123 its reverse (321123110100031), we get a palindrome (451124121421154).
The spelling of 130001011321123 in words is "one hundred thirty trillion, one billion, eleven million, three hundred twenty-one thousand, one hundred twenty-three".
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