130001012231131 has 2 divisors, whose sum is σ = 130001012231132. Its totient is φ = 130001012231130.

The previous prime is 130001012231117. The next prime is 130001012231137. The reversal of 130001012231131 is 131132210100031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130001012231131 - 2¹⁵ = 130001012198363 is a prime.

It is a super-2 number, since 2×130001012231131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130001012231099 and 130001012231108.

It is not a weakly prime, because it can be changed into another prime (130001012231137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000506115565 + 65000506115566.

It is an arithmetic number, because the mean of its divisors is an integer number (65000506115566).

Almost surely, 2^{130001012231131} is an apocalyptic number.

130001012231131 is a deficient number, since it is larger than the sum of its proper divisors (1).

130001012231131 is an equidigital number, since it uses as much as digits as its factorization.

130001012231131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 130001012231131 its reverse (131132210100031), we get a palindrome (261133222331162).

The spelling of 130001012231131 in words is "one hundred thirty trillion, one billion, twelve million, two hundred thirty-one thousand, one hundred thirty-one".