13000102021 has 4 divisors (see below), whose sum is σ = 13565323872. Its totient is φ = 12434880172.

The previous prime is 13000102013. The next prime is 13000102069. The reversal of 13000102021 is 12020100031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13000102021 - 2³ = 13000102013 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13000101989 and 13000102007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000102091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 282610891 + ... + 282610936.

It is an arithmetic number, because the mean of its divisors is an integer number (3391330968).

Almost surely, 2^13000102021 is an apocalyptic number.

It is an amenable number.

13000102021 is a deficient number, since it is larger than the sum of its proper divisors (565221851).

13000102021 is an equidigital number, since it uses as much as digits as its factorization.

13000102021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 565221850.

The product of its (nonzero) digits is 12, while the sum is 10.

Adding to 13000102021 its reverse (12020100031), we get a palindrome (25020202052).

It can be divided in two parts, 1300010 and 2021, that added together give a palindrome (1302031).

The spelling of 13000102021 in words is "thirteen billion, one hundred two thousand, twenty-one".