13000111001 has 2 divisors, whose sum is σ = 13000111002. Its totient is φ = 13000111000.

The previous prime is 13000110979. The next prime is 13000111031. The reversal of 13000111001 is 10011100031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7170024976 + 5830086025 = 84676^2 + 76355^2 .

It is an emirp because it is prime and its reverse (10011100031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13000111001 - 2¹⁴ = 13000094617 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13000111001.

It is not a weakly prime, because it can be changed into another prime (13000111031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500055500 + 6500055501.

It is an arithmetic number, because the mean of its divisors is an integer number (6500055501).

Almost surely, 2^13000111001 is an apocalyptic number.

It is an amenable number.

13000111001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000111001 is an equidigital number, since it uses as much as digits as its factorization.

13000111001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 13000111001 its reverse (10011100031), we get a palindrome (23011211032).

The spelling of 13000111001 in words is "thirteen billion, one hundred eleven thousand, one".