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13000111109977 is a prime number
BaseRepresentation
bin1011110100101101001100…
…0000010011011101011001
31201000210120002120111111211
42331023103000103131121
53200443211421004402
643352100230023121
72511140605125235
oct275132300233531
951023502514454
1013000111109977
11416235289a322
12155b612aa7aa1
13733b9c9bba74
1432d2ccaa95c5
151782692d34d7
hexbd2d3013759

13000111109977 has 2 divisors, whose sum is σ = 13000111109978. Its totient is φ = 13000111109976.

The previous prime is 13000111109911. The next prime is 13000111110031. The reversal of 13000111109977 is 77990111100031.

13000111109977 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12915765010201 + 84346099776 = 3593851^2 + 290424^2 .

It is a cyclic number.

It is not a de Polignac number, because 13000111109977 - 227 = 12999976892249 is a prime.

It is not a weakly prime, because it can be changed into another prime (13000115109977) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500055554988 + 6500055554989.

It is an arithmetic number, because the mean of its divisors is an integer number (6500055554989).

Almost surely, 213000111109977 is an apocalyptic number.

It is an amenable number.

13000111109977 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000111109977 is an equidigital number, since it uses as much as digits as its factorization.

13000111109977 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11907, while the sum is 40.

The spelling of 13000111109977 in words is "thirteen trillion, one hundred eleven million, one hundred nine thousand, nine hundred seventy-seven".