Base | Representation |
---|---|
bin | 11101100011110000111111… |
… | …011100000010110010101100 |
3 | 122001021222122120122101002202 |
4 | 131203300333130002302230 |
5 | 114014414310403301104 |
6 | 1140253410252441032 |
7 | 36245162205210605 |
oct | 3543607734026254 |
9 | 561258576571082 |
10 | 130001134431404 |
11 | 3847119829a345 |
12 | 126b7110a79178 |
13 | 57700925ccb82 |
14 | 2416134b00dac |
15 | 1006963e8151e |
hex | 763c3f702cac |
130001134431404 has 24 divisors (see below), whose sum is σ = 238073586223200. Its totient is φ = 61996305279744.
The previous prime is 130001134431373. The next prime is 130001134431407. The reversal of 130001134431404 is 404134431100031.
It is a super-2 number, since 2×1300011344314042 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (130001134431407) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2024403149 + ... + 2024467364.
It is an arithmetic number, because the mean of its divisors is an integer number (9919732759300).
Almost surely, 2130001134431404 is an apocalyptic number.
It is an amenable number.
130001134431404 is a deficient number, since it is larger than the sum of its proper divisors (108072451791796).
130001134431404 is a wasteful number, since it uses less digits than its factorization.
130001134431404 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4048870889 (or 4048870887 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 130001134431404 its reverse (404134431100031), we get a palindrome (534135565531435).
The spelling of 130001134431404 in words is "one hundred thirty trillion, one billion, one hundred thirty-four million, four hundred thirty-one thousand, four hundred four".
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