1300012443421 has 4 divisors (see below), whose sum is σ = 1300028810652. Its totient is φ = 1299996076192.

The previous prime is 1300012443347. The next prime is 1300012443491. The reversal of 1300012443421 is 1243442100031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 237904940025 + 1062107503396 = 487755^2 + 1030586^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300012443421 - 2²⁷ = 1299878225693 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300012443491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8063890 + ... + 8223523.

It is an arithmetic number, because the mean of its divisors is an integer number (325007202663).

Almost surely, 2^{1300012443421} is an apocalyptic number.

It is an amenable number.

1300012443421 is a deficient number, since it is larger than the sum of its proper divisors (16367231).

1300012443421 is an equidigital number, since it uses as much as digits as its factorization.

1300012443421 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16367230.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1300012443421 its reverse (1243442100031), we get a palindrome (2543454543452).

The spelling of 1300012443421 in words is "one trillion, three hundred billion, twelve million, four hundred forty-three thousand, four hundred twenty-one".