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1300012714200 = 2335219599072131
BaseRepresentation
bin10010111010101110110…
…010111100100011011000
311121021120010021101211110
4102322232302330203120
5132244411223323300
62433115000100320
7162631345514124
oct22725662744330
94537503241743
101300012714200
114613723165a2
1218bb4b7646a0
139578a929535
1446cc7138584
1523c3a0d7550
hex12eaecbc8d8

1300012714200 has 384 divisors, whose sum is σ = 4320830592000. Its totient is φ = 322350451200.

The previous prime is 1300012714171. The next prime is 1300012714211. The reversal of 1300012714200 is 24172100031.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 610047135 + ... + 610049265.

It is an arithmetic number, because the mean of its divisors is an integer number (11252163000).

Almost surely, 21300012714200 is an apocalyptic number.

1300012714200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1300012714200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2160415296000).

1300012714200 is an abundant number, since it is smaller than the sum of its proper divisors (3020817877800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300012714200 is a wasteful number, since it uses less digits than its factorization.

1300012714200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3135 (or 3126 counting only the distinct ones).

The product of its (nonzero) digits is 336, while the sum is 21.

Adding to 1300012714200 its reverse (24172100031), we get a palindrome (1324184814231).

The spelling of 1300012714200 in words is "one trillion, three hundred billion, twelve million, seven hundred fourteen thousand, two hundred".