Base | Representation |
---|---|
bin | 111100100010010101… |
… | …1101001110101100000 |
3 | 110102120000101221212220 |
4 | 1321010223221311200 |
5 | 4112220314004440 |
6 | 135415523151040 |
7 | 12251360633460 |
oct | 1710453516540 |
9 | 412500357786 |
10 | 130001313120 |
11 | 50151396758 |
12 | 21241215480 |
13 | c34a244423 |
14 | 641372bba0 |
15 | 35ad0228d0 |
hex | 1e44ae9d60 |
130001313120 has 192 divisors, whose sum is σ = 468253094400. Its totient is φ = 29698818048.
The previous prime is 130001313107. The next prime is 130001313137. The reversal of 130001313120 is 21313100031.
130001313120 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 130001313120.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7043424 + ... + 7061856.
It is an arithmetic number, because the mean of its divisors is an integer number (2438818200).
Almost surely, 2130001313120 is an apocalyptic number.
130001313120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130001313120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (234126547200).
130001313120 is an abundant number, since it is smaller than the sum of its proper divisors (338251781280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130001313120 is a wasteful number, since it uses less digits than its factorization.
130001313120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20557 (or 20549 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 130001313120 its reverse (21313100031), we get a palindrome (151314413151).
The spelling of 130001313120 in words is "one hundred thirty billion, one million, three hundred thirteen thousand, one hundred twenty".
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