Base | Representation |
---|---|
bin | 1011110100101101100100… |
… | …1001101000110110101100 |
3 | 1201000210211021121001011010 |
4 | 2331023121021220312230 |
5 | 3200443414320021304 |
6 | 43352114352025220 |
7 | 2511143266423161 |
oct | 275133111506654 |
9 | 51023737531133 |
10 | 13000214220204 |
11 | 41623a6015592 |
12 | 155b641532210 |
13 | 733bb8181133 |
14 | 32d2dc66a068 |
15 | 17827339e789 |
hex | bd2d9268dac |
13000214220204 has 24 divisors (see below), whose sum is σ = 30345113967280. Its totient is φ = 4331793199104.
The previous prime is 13000214220193. The next prime is 13000214220241. The reversal of 13000214220204 is 40202241200031.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 201409009 + ... + 201473544.
Almost surely, 213000214220204 is an apocalyptic number.
It is an amenable number.
13000214220204 is an abundant number, since it is smaller than the sum of its proper divisors (17344899747076).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13000214220204 is a wasteful number, since it uses less digits than its factorization.
13000214220204 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 402885249 (or 402885247 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 21.
Adding to 13000214220204 its reverse (40202241200031), we get a palindrome (53202455420235).
The spelling of 13000214220204 in words is "thirteen trillion, two hundred fourteen million, two hundred twenty thousand, two hundred four".
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