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13000230625143 = 37820355412327
BaseRepresentation
bin1011110100101101101000…
…1000001101111101110111
31201000210212102110111111110
42331023122020031331313
53200443433020001033
643352120135410103
72511143556030036
oct275133210157567
951023772414443
1013000230625143
1141624042aa893
12155b646b23933
13733bbb6a60b8
1432d3008da71d
15178274a40363
hexbd2da20df77

13000230625143 has 8 divisors (see below), whose sum is σ = 17333862795648. Its totient is φ = 8666709435704.

The previous prime is 13000230625093. The next prime is 13000230625259. The reversal of 13000230625143 is 34152603200031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13000230625143 - 26 = 13000230625079 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13000230625143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000230625043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27471555 + ... + 27940772.

It is an arithmetic number, because the mean of its divisors is an integer number (2166732849456).

Almost surely, 213000230625143 is an apocalyptic number.

13000230625143 is a deficient number, since it is larger than the sum of its proper divisors (4333632170505).

13000230625143 is an equidigital number, since it uses as much as digits as its factorization.

13000230625143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55490533.

The product of its (nonzero) digits is 12960, while the sum is 30.

Adding to 13000230625143 its reverse (34152603200031), we get a palindrome (47152833825174).

The spelling of 13000230625143 in words is "thirteen trillion, two hundred thirty million, six hundred twenty-five thousand, one hundred forty-three".

Divisors: 1 3 78203 234609 55412327 166236981 4333410208381 13000230625143