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130002323102 = 265001161551
BaseRepresentation
bin111100100010010111…
…1100000011010011110
3110102120002022021022122
41321010233200122132
54112221043314402
6135420000542542
712251402341151
oct1710457403236
9412502267278
10130002323102
1150151a16553
1221241621a52
13c34a509052
146413911c98
1535ad171ca2
hex1e44be069e

130002323102 has 4 divisors (see below), whose sum is σ = 195003484656. Its totient is φ = 65001161550.

The previous prime is 130002323081. The next prime is 130002323107. The reversal of 130002323102 is 201323200031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 201323200031 = 523384939197.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130002323107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32500580774 + ... + 32500580777.

It is an arithmetic number, because the mean of its divisors is an integer number (48750871164).

Almost surely, 2130002323102 is an apocalyptic number.

130002323102 is a deficient number, since it is larger than the sum of its proper divisors (65001161554).

130002323102 is an equidigital number, since it uses as much as digits as its factorization.

130002323102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65001161553.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 130002323102 its reverse (201323200031), we get a palindrome (331325523133).

The spelling of 130002323102 in words is "one hundred thirty billion, two million, three hundred twenty-three thousand, one hundred two".

Divisors: 1 2 65001161551 130002323102