Base | Representation |
---|---|
bin | 11101100011110010000111… |
… | …010100001100011000001011 |
3 | 122001022002202121202112012022 |
4 | 131203302013110030120023 |
5 | 114014424243111124232 |
6 | 1140254130051235055 |
7 | 36245234120206106 |
oct | 3543620724143013 |
9 | 561262677675168 |
10 | 130002340333067 |
11 | 38471756a67094 |
12 | 126b73a88a8a8b |
13 | 57702253ac657 |
14 | 241620ad2973d |
15 | 10069d4c85812 |
hex | 763c8750c60b |
130002340333067 has 2 divisors, whose sum is σ = 130002340333068. Its totient is φ = 130002340333066.
The previous prime is 130002340333037. The next prime is 130002340333087. The reversal of 130002340333067 is 760333043200031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130002340333067 - 220 = 130002339284491 is a prime.
It is not a weakly prime, because it can be changed into another prime (130002340333007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65001170166533 + 65001170166534.
It is an arithmetic number, because the mean of its divisors is an integer number (65001170166534).
Almost surely, 2130002340333067 is an apocalyptic number.
130002340333067 is a deficient number, since it is larger than the sum of its proper divisors (1).
130002340333067 is an equidigital number, since it uses as much as digits as its factorization.
130002340333067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81648, while the sum is 35.
Adding to 130002340333067 its reverse (760333043200031), we get a palindrome (890335383533098).
The spelling of 130002340333067 in words is "one hundred thirty trillion, two billion, three hundred forty million, three hundred thirty-three thousand, sixty-seven".
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