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1300026553122 = 2311234359794273
BaseRepresentation
bin10010111010101111100…
…111101111001100100010
311121021121002022111021010
4102322233213233030202
5132244423244144442
62433120212441350
7162631604242623
oct22725747571442
94537532274233
101300026553122
1146137a108a20
1218bb54319256
139579076354b
1446cc8cdba4a
1523c3b41cb9c
hex12eaf9ef322

1300026553122 has 256 divisors, whose sum is σ = 3119623372800. Its totient is φ = 357154237440.

The previous prime is 1300026553109. The next prime is 1300026553129. The reversal of 1300026553122 is 2213556200031.

It is a self number, because there is not a number n which added to its sum of digits gives 1300026553122.

It is not an unprimeable number, because it can be changed into a prime (1300026553129) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 304239978 + ... + 304244250.

It is an arithmetic number, because the mean of its divisors is an integer number (12186028800).

Almost surely, 21300026553122 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1300026553122, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1559811686400).

1300026553122 is an abundant number, since it is smaller than the sum of its proper divisors (1819596819678).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300026553122 is a wasteful number, since it uses less digits than its factorization.

1300026553122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4493.

The product of its (nonzero) digits is 10800, while the sum is 30.

The spelling of 1300026553122 in words is "one trillion, three hundred billion, twenty-six million, five hundred fifty-three thousand, one hundred twenty-two".