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13000300210153 is a prime number
BaseRepresentation
bin1011110100101101111001…
…0001101010011111101001
31201000211001021101210012001
42331023132101222133221
53200444103323211103
643352131103051001
72511145362344554
oct275133621523751
951024037353161
1013000300210153
11416243a608063
12155b6662a0a61
13733bccc2aa69
1432d309c5169b
1517827abd801d
hexbd2de46a7e9

13000300210153 has 2 divisors, whose sum is σ = 13000300210154. Its totient is φ = 13000300210152.

The previous prime is 13000300210133. The next prime is 13000300210213. The reversal of 13000300210153 is 35101200300031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11605652583849 + 1394647626304 = 3406707^2 + 1180952^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13000300210153 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13000300210153.

It is not a weakly prime, because it can be changed into another prime (13000300210133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500150105076 + 6500150105077.

It is an arithmetic number, because the mean of its divisors is an integer number (6500150105077).

Almost surely, 213000300210153 is an apocalyptic number.

It is an amenable number.

13000300210153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000300210153 is an equidigital number, since it uses as much as digits as its factorization.

13000300210153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 270, while the sum is 19.

Adding to 13000300210153 its reverse (35101200300031), we get a palindrome (48101500510184).

The spelling of 13000300210153 in words is "thirteen trillion, three hundred million, two hundred ten thousand, one hundred fifty-three".