13000300211 has 2 divisors, whose sum is σ = 13000300212. Its totient is φ = 13000300210.

The previous prime is 13000300207. The next prime is 13000300249. The reversal of 13000300211 is 11200300031.

13000300211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13000300211 - 2² = 13000300207 is a prime.

It is a super-2 number, since 2×13000300211² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13000300192 and 13000300201.

It is not a weakly prime, because it can be changed into another prime (13000305211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500150105 + 6500150106.

It is an arithmetic number, because the mean of its divisors is an integer number (6500150106).

Almost surely, 2^13000300211 is an apocalyptic number.

13000300211 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000300211 is an equidigital number, since it uses as much as digits as its factorization.

13000300211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 13000300211 its reverse (11200300031), we get a palindrome (24200600242).

The spelling of 13000300211 in words is "thirteen billion, three hundred thousand, two hundred eleven".