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13000302223147 is a prime number
BaseRepresentation
bin1011110100101101111001…
…1001010101111100101011
31201000211001102012001111101
42331023132121111330223
53200444104332120042
643352131214142231
72511145415430421
oct275133631257453
951024042161441
1013000302223147
114162440762498
12155b666ab1977
13733c00484095
1432d30a217111
1517827ae846b7
hexbd2de655f2b

13000302223147 has 2 divisors, whose sum is σ = 13000302223148. Its totient is φ = 13000302223146.

The previous prime is 13000302223061. The next prime is 13000302223169. The reversal of 13000302223147 is 74132220300031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13000302223147 is a prime.

It is not a weakly prime, because it can be changed into another prime (13000302221147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500151111573 + 6500151111574.

It is an arithmetic number, because the mean of its divisors is an integer number (6500151111574).

Almost surely, 213000302223147 is an apocalyptic number.

13000302223147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000302223147 is an equidigital number, since it uses as much as digits as its factorization.

13000302223147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 28.

Adding to 13000302223147 its reverse (74132220300031), we get a palindrome (87132522523178).

The spelling of 13000302223147 in words is "thirteen trillion, three hundred two million, two hundred twenty-three thousand, one hundred forty-seven".