Base | Representation |
---|---|
bin | 1011110100101101111001… |
… | …1001010101111100101011 |
3 | 1201000211001102012001111101 |
4 | 2331023132121111330223 |
5 | 3200444104332120042 |
6 | 43352131214142231 |
7 | 2511145415430421 |
oct | 275133631257453 |
9 | 51024042161441 |
10 | 13000302223147 |
11 | 4162440762498 |
12 | 155b666ab1977 |
13 | 733c00484095 |
14 | 32d30a217111 |
15 | 17827ae846b7 |
hex | bd2de655f2b |
13000302223147 has 2 divisors, whose sum is σ = 13000302223148. Its totient is φ = 13000302223146.
The previous prime is 13000302223061. The next prime is 13000302223169. The reversal of 13000302223147 is 74132220300031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13000302223147 is a prime.
It is not a weakly prime, because it can be changed into another prime (13000302221147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500151111573 + 6500151111574.
It is an arithmetic number, because the mean of its divisors is an integer number (6500151111574).
Almost surely, 213000302223147 is an apocalyptic number.
13000302223147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13000302223147 is an equidigital number, since it uses as much as digits as its factorization.
13000302223147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 13000302223147 its reverse (74132220300031), we get a palindrome (87132522523178).
The spelling of 13000302223147 in words is "thirteen trillion, three hundred two million, two hundred twenty-three thousand, one hundred forty-seven".
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