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13000303124000 = 255341109727249
BaseRepresentation
bin1011110100101101111001…
…1100110001111000100000
31201000211001110212211020022
42331023132130301320200
53200444110044432000
643352131245333012
72511145426202003
oct275133634617040
951024043784208
1013000303124000
1141624412182a5
12155b667267168
13733c0070b12a
1432d30a3ad53a
1517827b0b1585
hexbd2de731e20

13000303124000 has 192 divisors, whose sum is σ = 33021048060000. Its totient is φ = 5026738176000.

The previous prime is 13000303123939. The next prime is 13000303124023. The reversal of 13000303124000 is 42130300031.

It is a happy number.

It can be written as a sum of positive squares in 16 ways, for example, as 3744519125776 + 9255783998224 = 1935076^2 + 3042332^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 13000303124000.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 17512376 + ... + 18239624.

Almost surely, 213000303124000 is an apocalyptic number.

13000303124000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13000303124000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16510524030000).

13000303124000 is an abundant number, since it is smaller than the sum of its proper divisors (20020744936000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13000303124000 is a wasteful number, since it uses less digits than its factorization.

13000303124000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 727424 (or 727406 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 13000303124000 its reverse (42130300031), we get a palindrome (13042433424031).

The spelling of 13000303124000 in words is "thirteen trillion, three hundred three million, one hundred twenty-four thousand".